### ScubaSteves Scribe Post #2-Review of assignments?!

Well hello there from Cyber-Math World, fellow classmates! This is ScubaSteve reporting for the second time. First off, today was a double class, and we also had a test. But thanks to somebody (not pointing any fingers >_>) we had it on the second class, but I for one, like many knowing alot of us are just dying to get it over with.

Well well, we had a hand out, and some online questions. A handful of people were bravely enough to put up their hand and ask. (I say bravely, I know there would be more, hoping their questions would be answered by a fellow sucke-- err im mean classmate. =]) Well, lets get on it shall we? Of course!. (talking to himself)

__In terms of real numbers__

To begin with, we give ourselves the oh so sexy formula that Mr.K made up to help solve this kind of problem, simple put as:

t= 0 in 1995

Ao= 1 (we put 1 because it can be used to describe the "first" amount)

It will take 31.8520 years for Calgary's population to double.

__In terms of e__

6(10^5) = 3(10^5)e^(kt)

2=e^(kt)

ln2/k=t

t=4.8188

The time would be 4 o'clock and 0.8188 hours (Im kind of clueless right now how to convert that to minutes >_> oh shame to me.)

3^(2x-1)+1=2

3^(2x-1)=1 (bring the 1 over)

2x-1=0 (both having the same base the exponents have a little party of their own in the form of an equation!)

2x=1

x=(1/2)

5./([4^3]-2)/[8^(x+1)]) = 16

([(2^2)(3x-2)]/(2^3)(x+1))^(1/5) = 2^4

((2^(6x-4))/2^(3x+3)^(1/5) = 2^4

(2x^(3x-7))^(1/5) = 2^4

2^(3x-7) = 2^20

3x-7 = 20

3x = 27

x = 9

It gets big easily. So, now that we've added the ties, u can see there are 12 combinations possible.

Easy huh? Well after that, Mr.K decided to grab 4 students out of their chairs and stand infront of the class. He then explained how many combinations would there be for 4 students to sit in 4 chairs? Given that once one student had sat down, there would only be three combinations left. And so forth. Then he explained how to calculate this easily he wrote simply this on the board: 4!

No, not 4! as in I REALLY ment it. But 4! as in 4*3*2*1.

So what if it was 5!, then it would be 5*4*3*2*1, remember that it stops at 1, because if it reaches 0 it all becomes 0, and if its a negitive number, well it wouldn't make sense.

Variably it would be: n!=n(n-1)(n-2)(n-3)....3(2)1

Well if you've reached this far, you'll see a light at the end of the tunnel. This concludes the behemoth of a scribe post! Because Mr.K had been called down... to take a picture o_o;; Well, that and my fingers are getting really sore from typing all this. Ooh ooh, speaking about pictures being taken. After all that reading, enjoy this short, even thought it's about mother's day I still think it makes sense for this umm, current rambling. Enjoy, ScubaSteve out~!

Hey Scubasteve, love your scribe post! So detailed and what caught my eyes the most was how much images you put into it.. you must have worked very hard on it. But good job!

ReplyDeletehey steve, love the post! didn't think you would do better than your last post, but you did! good work! it was colourful and very detailed. all scribe posts should be like this, it catches someones eyes. hall of fame for you my friend!

ReplyDeleteanother job well done my friend! your post was amazing! it was colorful and organized, it was funny and interesting....hehehe i like the video

ReplyDeleteHey Steve... everyone is right this is really good... the pictures and colors do really catch the eye and make you want to read everything... i really like your approach to scribe posts... being creative is really effective.. you definitely have my vote for hall of fame... Good Job!!

ReplyDeleteI'M VOTING YOU TO GET INTO THE HALL OF FAME! YOU EARNED IT!

ReplyDeleteHi Scubasteve,

ReplyDeleteAdd me to list of suggesting this scribe is Hall of Fame worthy!!

You've kept the attention of your audience throughout!!!

Best,

Lani

HALL OF FAME DOODE ! this post was awesome ! =)

ReplyDelete