## October 31, 2006

### Logarithms Homework

(1) Solve for x:
(a) log8x = 2
(b) log4x = -(3/2)
(c) logx27 = (3/2)
(d) logx5 = -(1/2)

(2) Expand:
(a) log2M5N4
(b) log2(M4/N3)

(3) Given that log109 = 0.95 and log102 = 0.30, without using a calculator evaluate:
(a) log1081
(b) log103
(c) log10(9/2)
(d) log10(1/2000)

scroll way down for the answers ....

don't look until you're tried all the questions ....

HEY .... no peeking!!!!!! ;-)

Wonder what this picture has to do with logarithms ....

... something ... can you figure out what? ;-)

(1) (a) 64 (b) 1/8 (c) 9 (d) 1/25
(2) (a) 5log2M + 4log2N (b) you figure it out. ;-)
(3) (a) 1.9 (b) 0.475 (c) 0.65 (d) -3.30

1. Does anyone know HOW to answer the last questions ? I'm having trouble.

2. this is my solution..
for the last, last question:

log<10> (1/2000)

since:
log<10> 1 = 0
log<10> 10 = 1
log<10> 2 = .30

log<10>1 - (log<10>10 + log<10>10 + log<10>10 + log<10>2

so..

0 - (1+1+1+.30)
= -3.30

3. Oh i see ! i get it now thanks richard !