Scribe Post: Trigonometric Modeling
After the quiz on transformation, a new lesson was discussed to us. It was the Trigonometric Modeling which has something to do with circular functions and transformations. Mr. K gave us this example:
172 days
( Note: This graph is not accurate)
Since the graph has only a half wave, It means that it only has a half period. A full period makes one wave. By looking at the garph, you can easily get the period.
FINDING THE PERIOD
Half Period = 355 days - 172 days
= 183 days
Full Period = 2 (183 days)
= 366 days
Quarter Period = 1/2 (183 days)
= 91.5 days
As soon as you know the period, you can now complete the graph. You have to draw the other half of the wave. To obtain the x-coordinates where the other max lies subtract 172 to the half period. So -11 is the location of the other max.
By also knowing the period, you can determine the day where the average sunrise time occurs.
You already know that the max and min has the same measure from sinusoidal axis. Since the point from the sinusoidal axis to the max or min is equal to quarter period, you can get the value of that point by getting the average of its max and min.
First point
max - 11
min 172
-11 + 172
________ = 80.5 days
2
Second point
max 355
min 172
355 + 172
________ = 263.5 days
2
So the average sunrise will fall on the 80th 1/2 day and 263 1/2 day.
At this point, we had figured out the answers in A and D. Until, kriiiiiinnnnggg! The bell rang. Our class period is over. We called it a day. JhoAnn will now continue the rest of the answers. I hope you gain something to my scribe.
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